Free All India JEE Main Mock Test by Amazon Dec 27 - Study Pirates

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Saturday, December 7, 2019

Free All India JEE Main Mock Test by Amazon Dec 27

Free All India JEE Main Mock Test by Amazon Dec 27: Registrations Open


Amazon is hosting a free, high-quality mock test (AIMT – All India Mock Test) based on the new JEE 2020 pattern, designed by subject matter experts from Sri Chaitanya Institutions.

With this test, you can:

  1. Benchmark your performance across a broader set of fellow JEE aspirants with the all India rank and percentile score.
  2. Get in-depth time and strength/weakness analysis.
  3. Get personalized performance report with rich and deep learning analytics.

  • Test Pattern
 The mock test is based on the new JEE Main pattern and is of three hours duration. The test will include a total of 75 questions with 25 each for Physics, Chemistry, and Mathematics. Out of the total of 75 questions, 60 will be multiple-choice type questions (MCQs), and the remaining 15 will be numerical. While there is negative marking for incorrect responses to the MCQs, the numerical questions will not have any negative marking.

Syllabus and Timings

AIMT is based on the JEE Main syllabus and will simulate the real exam pattern. AIMT is scheduled for December 27, 2019. Students can begin the test at their convenience by picking one of these time-slots:

9 AM – 12 PM or
2 PM – 5 PM or
7 PM – 10 PM IST.
Test papers will not repeat across these three-time slots.

AIMT results will be published on December 28, 2019, at 5 PM.
To register for the All India Mock Test, click here.








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